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Sedbober [7]
3 years ago
6

Please help me someone​

Mathematics
1 answer:
Airida [17]3 years ago
3 0
I think the last one but I could be wrong
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aquil had $40. he spent 2/5 of his money on a new hat. he spent 1/2 of what was left on sunglasses. how much money did he have l
grandymaker [24]

Answer:

money left= 16

hat and jersey together= 24

Step-by-step explanation:

40(2/5)=16

16(1/2)=8

8 0
3 years ago
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1 a.) 20cm^2 to mm^2
mixas84 [53]

Answer:

a) 200 mm^2

b) 500 mm^2

c) 3.75e + 8

d) 6390 cm^2

e) 650 cm^2

f) 20 m/s

Step-by-step explanation:

For a) and b): 1 cm = 10 mm, multiply 20 (and 50) by 10

For c): the formula is to multiply 1e + 8

For d): 1 Liter = 1000 Cubic Centimeters  (hopefully that's what you're referring to)

For e): 10 mm = 1 cm, divide by 10

For f): divide the value by 3.6

6 0
3 years ago
State the missing angle
Anettt [7]

Answer:

  • zhshhunvsisiiniabiwbgihwqnowowjwg gap
6 0
3 years ago
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Find the domain and range of the function graphed below.
anyanavicka [17]

domain = [-3 , 1)

range = [-5 , 4]

have a nice day

and this shape ( and that [ matters so be careful.

7 0
2 years ago
The diagonals of a rhombus measures 6cm and 8cm, what is the perimeter of this rhombus?
Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

\setlength{\unitlength}{1 cm}\begin{picture}(20,15)\thicklines\qbezier(1,1)(1,1)(6,1)\qbezier(1,1)(1,1)(1.6,4)\qbezier(1.6,4)(1.6,4)(6.6,4)\qbezier(6,1)(6,1)(6.6,4)\qbezier(6.6,4)(6.6,4)(1,1)\qbezier(1.6,4)(1.6,4)(6,1)\put(0.7,0.5){\sf A}\put(6,0.5){\sf B}\put(1.4,4.3){\sf D}\put(6.6,4.3){\sf C}\end{picture}

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

  • Substitute the values

{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

5 0
3 years ago
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