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Mathematics

1 answer:

Airida [17]2 years ago

3 0

I think the last one but I could be wrong

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Akimi4 [234]

Answer:

Step-by-step explanation:

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2 years ago

Write the name of a shape that when reflected in the x-axis , will remain identical

olga55 [171]

A circle is one shape that can be reflected
Hope this helps :)

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2 years ago

Read 2 more answers

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

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3 years ago

Read 2 more answers

Help me I need this withing 3 hours

bulgar [2K]

Answer:

a. min: 6 1/2 max: 13 median: 8 1/50 range: 6 1/2 mode: 8

b. min: 8 1/2 max: 11 1/2 median: 9 7/10 range: 3 mode: 9 1/4

Step-by-step explanation:

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2 years ago

Winnie wrote the following riddle: I am a number between 60nand 100. My ones digit is two less than my tens digit. I am a prime

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3 years ago

Please help me someone​

Please help me someone