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3 years ago

PLEASE HELP ITS A TIMED TEST!!!

Mathematics

1 answer:

nexus9112 [7]3 years ago

8 0

Answer:

First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.

To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.

240 = 25x + 40

subtract 40 from each side

200= 25x

divide by 25

8 = x

8 months

10 + 7r = 45

7r = 35

r = 5

5 milesStep-by-step explanation:

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A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

Bacteria entering the human body can cause infections and diseases. The human body must respond to fight the bacteria.

Masja [62]

Answer:

d looks like the best option. sorry if its isn't

7 0

3 years ago

HELP ME PLEASE :( I’m confused

Maksim231197 [3]

Answer:

11) I haven't done these yet don't go by my answers wait for more responses.

So if TR looks exactly half way from the middle and it says its 11, and if PS is basically two of TR then it would be 22. It looks to me that TR is 11 which is exactly half way I think, and PS looks double of TR so 2 x 11 = 22. Please go by the way you learned i don't know if I'm right.

12) If MK is exactly straight and its 10, half of 10 would be 5. I did half of 10 because L to M looks as if it is 10 already but since its L to the point in the middle that would be half way of the total line from L to M. So L to the point must be 5, MK is already given which is 10 so now we add 5 since L to the point in the middle is half way of 10 which is 5.

10(MK) + 5(L to the point in the middle of the circle) = 15

I don't want to be the one who brings your grades down so do by the way you learned.

8 0

3 years ago

Find the sum of odd integers from 1 through 57

HACTEHA [7]

Answer:

Step-by-step explanation:

First we find n:

Tn = a+ (n-1)d

Here,

a=1 ,Tn =57

d=2 ( difference between numbers is 2)

Now,

57 = 1 + (n-1)2

57 = 2n -1

58/2 = n

Or n = 29

Now, We find sum :

Sn = n/2 { a+Tn}

= 29/2 { 1 + 57 }

= 29/2 ( 58)

= 29 x 29

= 841

3 0

3 years ago

Help with this math test

telo118 [61]

Answer:

blank 1 : 2

blank 2: 4

blank 3: 6

blank 4: 8

blank 5: 3

blank 6: 6

blank 7: 9

blank8: 12

Step-by-step explanation:

domain = first number

range = second number

4 0

3 years ago