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4 years ago

An object is launched from a platform.

Mathematics

2 answers:

uysha [10]4 years ago

7 0

Answer:

6seconds

Step-by-step explanation:

Given the height of an object modeled by the expression

h(x)=-5x^2+20x+60

The height of the object on the ground is zero i.e h(x) = 0

On substituting

h(x)=-5x^2+20x+60

0 =-5x^2+20x+60

Multiply through by -1

5x^2-20x- 60 = 0

Divide through by 5

x^2 - 4x - 12 = 0

x^2 - 6x + 2x - 12 = 0

x(x-6)+2(x-6) = 0

(x-6)(x+2) = 0

x - 6 = 0 and x+2 = 0

x = 6 and -2

Since time cannot be negative, hence it takes 6seconds after launch for the object land to on the ground

gregori [183]4 years ago

6 0

Answer:

Step-by-step explanation:

It was correct on Khan.

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Answer:

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S_A_V [24]

Answer:

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