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Alika [10]
3 years ago
7

How do you make 4/3 and 3/3 have a denominator of 5

Mathematics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

Step-by-step explanation:

Actually, you can't.  You could multiply the numerator and denominator of each 4/3 and 3/3 by 5, obtaining:

5(4)          5(3)

------ and --------

5(3)           5(3)

but this result has little practical value.  4/3 and 3/3 could be combined immediately, obtaining 7/3, if that's what you want to do, as the fractions already have the same denominator (3).

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The coldest temperature recorded in Alaska was –80°F. This was 10°F warmer than the coldest temperature recorded in Siberia. Whi
Klio2033 [76]

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10  =  -80

Let the coldest temperature in Alaska be x

The coldest temperature recorded in Alaska was –80°F

x  =  –80°F

Let the coldest temperature in Siberia be y

The coldest temperature recorded in Alaska was 10°F warmer than the coldest temperature recorded in Siberia

This can be interpreted as:

Coldest temperature in Alaska  =  Coldest temperature in Siberia  +  10

x    =  y   +   10................(*)

Since x = -80

Substitute x = -80 into equation (*)

-80   =   y    +   10

This can be re-written as:

y  +  10   =   -80

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10  =  -80

Learn more here: brainly.com/question/2159099

7 0
2 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
Find f(-5) if f(n) = n^3 + 3n^2
Andrew [12]
Plug in -5 for n
-5^3 + 3(-5)^2
-125 + 3(25) = -125 + 75 = -50
f(-5) = -50
6 0
3 years ago
Write the slope-intercept form of the equation of the line.<br> slope = 0, y - int=1
saveliy_v [14]

Answer:

y= 1

Step-by-step explanation:

This is because there will be no increase or decrease of x since we have no slope to take us there so it will remain constant at the y value

Hope This Helps :)

3 0
2 years ago
Read 2 more answers
7x + 6y = 10<br> x+y = 9
Ne4ueva [31]

Step-by-step explanation:

7x + 6y = 10

=>7x+y=10-6

=>x+y=4-7

=>x+y= -3

6 0
2 years ago
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