Given that the line passes through two points
(-2,-2) and (x1,y1)
Equation in point slope form is
y-y1 = m(x-x1)
substitute for slope
Hence equation of the line = ![\frac{y2-y1}{x2-x1} =[tex]y-y1 = \frac{-2-y1}{-2-x1}(x-x1)](https://tex.z-dn.net/?f=%5Cfrac%7By2-y1%7D%7Bx2-x1%7D%20%3D%5Btex%5Dy-y1%20%3D%20%5Cfrac%7B-2-y1%7D%7B-2-x1%7D%28x-x1%29)
Since we donot know the value of x1or y1 the equation would contain x1, y1 also as answer.
Answer in point slope form is
Answer:It's called the "y intercept" and it's the y value of the point where the line intersects the y- axis. For this line, the y-intercept is "negative 1." You can find the y-intercept by looking at the graph and seeing which point crosses the y axis. This point will always have an x coordinate of zero.
Step-by-step explanation:
The Y intercept of a straight line is simply where the line crosses the Y axis.
Example
Y intercept
In the above diagram the line crosses the Y axis at 1.
The Y intercept is equal to 1 and the point is written as (0,1). Notice that for the y-intercept the x-coordinate of the point is always zero..
No. 1 is is always equal to to 1 .
In interval notation it should be [6, ∞)
