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DENIUS [597]
3 years ago
8

You need a 35% alcohol Solution on hand you have a 270 mL of a 30% alcohol mixture you also have 80% alcohol mixture how much of

the 80% mixture will you need to obtain the desired solution
you will need
_____mL of the 80% solution
_____mL of the desired 35% solution​
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0
Hdhdhdudbfbdjfndbfhhdhfud your welcom
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I need help on math hw
dolphi86 [110]

Answer:

which part do u need go in and what grade is this work on

4 0
3 years ago
Someone help me pls <br><br>47 as the sum of ______
Elanso [62]

9514 1404 393

Answer:

  (a) 6² +3² +1² +1² = 47

  (b) 5² +4² +2² +1² +1² = 47

  (c) 3³ +4² +2² = 47

Step-by-step explanation:

It can work reasonably well to start with the largest square less than the target number, repeating that approach for the remaining differences. When more squares than necessary are asked for, then the first square chosen may need to be the square of a number 1 less than the largest possible.

The approach where a cube is required can work the same way.

(a) floor(√47) = 6; floor(√(47 -6^2)) = 3; floor(√(47 -45)) = 1; floor(√(47-46)) = 1

__

(b) floor(√47 -1) = 5; floor(√(47-25)) = 4; ...

__

(c) floor(∛47) = 3; floor(√(47 -27)) = 4; floor(√(47 -43)) = 2

3 0
3 years ago
For a craft project, two equilateral triangles are taped together to create a quadrilateral.
Anika [276]
If these are the missing parts: 

What is the quadrilateral?

a.rhombus
b. rectangle
c. trapezoid
<span>d. square

The quadrilateral formed by the </span><span>two equilateral triangles taped together is A. RHOMBUS.

Rhombus has equal sides but its is different from a square because it looks like a diamond. 
Rhombus also have parallel opposite sides and equal opposite angles. </span>

3 0
3 years ago
Read 2 more answers
Fifteen gallons of gasoline can be represented by the coordinates (15,40.8) true or false
sineoko [7]

Answer:

false?

Step-by-step explanation:

4 0
3 years ago
If x= sin theta then x/√1-x^2 is​
SCORPION-xisa [38]

Well,

Given that x=\sin(\theta),

We can rewrite the equation like,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}

Now use, \cos(\theta)^2+\sin(\theta)^2=1 which implies that 1-\sin(\theta)^2=\cos(\theta)^2

That means that,

\dfrac{\sin(\theta)}{\sqrt{1-\sin(\theta)^2}}\Longleftrightarrow\dfrac{\sin(\theta)}{\sqrt{\cos(\theta)^2}}

By def \sqrt{x^2}=x therefore \sqrt{\cos(\theta)^2}=\cos(\theta)

So the fraction now looks like,

\dfrac{\sin(\theta)}{\cos(\theta)}

Which is equal to the identity,

\boxed{\tan(\theta)}=\dfrac{\sin(\theta)}{\cos(\theta)}

Hope this helps.

r3t40

6 0
3 years ago
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