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2 years ago

Find the surface area of the solid figure.

Mathematics

1 answer:

Ber [7]2 years ago

8 0

Answer:

perimeter of base- 22

hight- 20 I think??

Area of base-24

suface area- 48???????????

sorry if this isnt correct

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How do I solve 34 x 17 using an area model

givi [52]

Multiplying 34x 17 and you will get answer

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3 years ago

If the circumference of a circle is divided by the length of its diameter. whats the result

Mnenie [13.5K]

Answer:

3.14 or π (It's the same thing)

Step-by-step explanation:

If you divide the circumference by its diameter, the constant ratio is called Pi

8 0

3 years ago

You want to find the mean weight of the apples in a barrel. what do you need to do?

Sveta_85 [38]

If you want to find the weight of the apples in the barrel first you have to ( FIND THE TOTAL WEIGHT OF ALL THE APPLES AND DIVIDE BY ALL THE NUMBER OF APPLES)

4 0

3 years ago

a rectangle has an area of 102 cm2. the length of the rectangle is 17 cm. what is the perimeter of the rectangle?

Kruka [31]

Area = length *width

102 = 17*w

w = 102/17 = 6

l=17
w=6

perimeter = 2l +2w
p = 2(l+w)
p=2*23

p = 46 cm

hope helped

4 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago