Splitting up the interval [0, 6] into 6 subintervals means we have
![[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]](https://tex.z-dn.net/?f=%5B0%2C1%5D%5Ccup%5B1%2C2%5D%5Ccup%5B2%2C3%5D%5Ccup%5Ccdots%5Ccup%5B5%2C6%5D)
and the respective midpoints are

. We can write these sequentially as

where

.
So the integral is approximately

Recall that



so our sum becomes

0.15 as fraction or multiply 3/8 and 2/5
14: 1 × 14
2 × 7
56: 1 × 56
2 × 28
4 × 14
7 × 8
63: 1 × 63
3 × 21
7 × 9
GCF(14, 56, 63) = 7
Step-by-step explanation:






option (4)
Answer:
8x^3
Step-by-step explanation:
(2x)3
=(2x)3
=2x*2x*2x
=8x^3