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Crazy boy [7]
3 years ago
13

Help please I’m stuck

Mathematics
2 answers:
Jlenok [28]3 years ago
4 0
12:4=3
9:3=3
so u multiply each side by 3 to get the second triangle..
answer: 4.5*3 =13.5
aniked [119]3 years ago
4 0

Answer:

k = 13.5 units

Step-by-step explanation:

Look for the similarity ratio.

Side YZ is similar to side BC because 9 is a factor of 3.

Side XZ is also similar to side AC since 12 is a factor of 4.

And the common thing between the factors is that they were both multiplied by 3.

3 × 3 = 9

4 × 3 = 12

So for the last side, which is 4.5, we have to multiply it by 3.

4.5 × 3 = 13.5

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Answer:

B

Step-by-step explanation:

Drop an altitude. Either of the two resulting right triangles with legs of length 5 and x and a hypotenuse of 10.

By the Pythagorean theorem, it follows that the answer is B.

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Please help me! And please explain how to solve this. Especially questions B, C, and E
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a gardener has 322 tulip bulbs she wants to plant rows of 15 bulbs how many bulbs can be planted how many bulbs will she have le
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Read 2 more answers
Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12
Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

\sf \longrightarrow 2y + 4x = 12 \\

\sf \longrightarrow 4x + 2y = 12

Firstly convert this into slope intercept form , to find out the slope of the line.

\sf \longrightarrow 2y = -4x +12\\

\sf \longrightarrow y =\dfrac{-4x+12}{2}\\

\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\

\sf \longrightarrow \red{ y = -2x + 6 }

Now on comparing it to slope intercept form which is y = mx + c , we have ,

  • m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}

Now we may use the point slope form of the line to find out the equation of the line using the given point . The point slope form is,

\sf \longrightarrow y - y_1 = m(x - x_1)

Now on substituting the respective values we have,

\sf \longrightarrow y - 1 = \dfrac{1}{2}(x-8)\\

\sf \longrightarrow 2(y-1 )= x -8 \\

\sf \longrightarrow 2y -2=x-8\\

\sf \longrightarrow \underline{\boxed{\bf 2y - x + 6=0}}

5 0
3 years ago
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