The answer to this question would be: at least 1566 can of food
In this question, each class at Briarwood Elementary collect at least 54 can of food and there are 29 classes. From that description you can get this equation:
1 class = 54 can of foods
Then for 29 class, the number of the can of food would be:
29 class * (54 can/class)= at least 1566 can of food
Answer:
x=12
Step-by-step explanation:
3x=2x+12
-2x from each side
x=12
Tan (65) = h/4
h = Tan(65) * 4
h = 2.1445 * 4
h = 8.578
h = 8.6 (rounded to the nearest tenth)
Answer:
8.6 ft
The answer is 0.
1 • -2 = -2
-2 + -2 = -4
-4 • -2 = 8
-8 + 8 = 0
0 • -2 = 0
The minimum that Nolan would have to spend is $33.84 while the maximum he has to spend is $35.94
<h3>How to solve for the minimum amount</h3>
10 * 0.84 = 8.4
8 * 1.29 = 10.32
8 * 1.89 = 15.12
The minimum is = 8.4 + 10.32 + 15.12
= 33.84 dollars.
<h3>How to solve for the maximum</h3>
10 * 1.89 = 18.9
8 * 1.29 = 10.32
8 * 0.84 = 6.72
The sum of the maximum is given as 18.9 + 10.32 + 6.72
= $35.94
<h3>Complete question</h3>
Edward Nolan has room for 26 bedding plants in his garden. He can get pansies for $1.89 each, marigolds for $1.29 each, and zinnias for $0.84 each. He plans to buy 10 of one type and 8 each of the other two types of plants. (a) What is the minimum (in $) Edward will have to spend? $ Incorrect: Your answer is incorrect. (b) What is the maximum (in $) Edward could spend? $ Incorrect: Your answer is incorrect.
Read more on maximum and minimum costs here:
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