Which of the following describes an isotope?
1 answer:
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Answer:
(a) reaction at each front wheel is 5272N (upward)
(b) force between boulder and pallet is 4124N (compression)
Explanation:
Acceleration of the truck = 1 m/
(to the left)
when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,
= 0.5 m/
(upward) ,
= 0.5 m/
(upward)
Let T be tension in the cable
pallet and boulder: ∑fy = ∑(fy)eff = 2T- ( +
)g = (
+
)
= 2T- (400 + 50)*(9.81 m/) = (400 + 50)*(0.5 m/
)
T = 2320N
Truck: = ∑(
)eff: =
(3.4m) +
(2.0m) - T (0.6m)=
(1.0m)
Nf = (2.0m)(2000 kg)(9.81 m/ )/3.4m - (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/
) = 11541.2N - 409.4N - 588.2N = 10544N
∑fy (upward) = ∑(fy)eff: +
-
g = 0
10544 + - (2000kg)(9.81 m/
) = 0
= 9076N
∑fx (to the left) = ∑(fx)eff: - T =
= 2320N + (2000kg)(9.81 m/
) = 4320N
(a) reaction at each front wheel:
1/2 (upward): 1/2 (10544N) = 5272N (upward)
(b) force between boulder and pallet:
∑fy (upward) = ∑(fy)eff: +
g -
= (400kg)(9.81 m/
) + (400kg)(0.5 m/
) = 4124N (compression)
Answer:
See the explanation below
Explanation:
We must solve this problem by defining that when we have a constant velocity, the acceleration is equal to zero. That is, when there is no speed change, there is no acceleration. We can understand it very easily by means of the following equation of kinematics.
where:
Vf = final velocity = 55 [km/h]
Vo = initial velocity = 55 [km/h]
a = acceleration [m/s²]
t = time [s]
As we can see there is no change in speed, and the difference between the two is equal to zero.