Answer:3.54ohms
Explanation: connection in parallel
1/Rt= 1/R1+1/R2+1/R3
1/Rt= 1/16+1/13+1/7
1/Rt= 91+112+208/1456
1/Rt= 411/1456
411Rt= 1456
Rt= 1456/411
Rt= 3.54ohms
Answer:
The speed is maximum and the acceleration is zero
Explanation:
- The speed of the mass in simple harmonic motion can be found by using the law of conservation of energy. In fact, the total mechanical energy of the mass-spring system is sum of kinetic energy and elastic potential energy:

where
m is the mass
v is the speed
k is the spring constant
x is the displacement
As we can see, when the displacement is zero (x=0), the term representing the kinetic energy is maximum, so v (the speed) is also maximum.
- The acceleration of the mass in simple harmonic motion is proportional to the restoring force acting on the mass, which is given by Hook's law

where
k is the spring constant
x is the displacement
When x = 0, F = 0, so the net force acting on the mass is zero. Therefore, this also means that the acceleration of the mass is also zero: a = 0.
Actually the question is not clear. The Benefit of lifting using lever is that you can apply force in a convenient direction and you can use very less force to lift object by balancing the torque due to object.For example you want to lift a mass of 4N with a force 2N you can use a class 2 lever and maintain the ratio between the distances of the body and the point of application of force from the fulcrum to be 1:2.In any case balance the torque to get the required force.
Answer:
so height is 0.1283 m
Explanation:
given data
height = 28 cm
diameter = 11 cm
cross-sectional area = 1.55 cm2
water flow rate = 2.46×10^−4 m3/s
to find out
How high will the water in the bucket rise
solution
we know that here
potential energy = kinetic energy
mgh = 1/2 mv²
multiply both sides by the 2 and we get
2mgh=mv²
solve it we get
√(2gh) = v ....................1
h = v²/2g ...............2
and
flow rate = A V
2.46×10^−4 = V 1.55×10^−4
V = 1.5870 m/s
so from 2
h = v²/2g
h = 1.5870²/ 2(9.81)
h = 0.1283 m
so height is 0.1283 m