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zaharov [31]
3 years ago
10

Solve the right triangle. Round decimal answers to the nearest tenth.

Mathematics
2 answers:
Alinara [238K]3 years ago
6 0
This guy is correct, his answer is not wrong
ra1l [238]3 years ago
3 0

Answer:

Step-by-step explanation:

14^2 = b^2+6^2\\b^2 = 14^2-6^2\\b = \sqrt{14^2-6^2} \\   = \sqrt{160}\\ = 12.6491106407

Rounding off to nearest tenth:

b ≈ 12.6

tanθ = 6/12.6

tan^{-1} (6/12.6)\\ = 25.46334506\\

Hence angle A ≈ 25.5

Angle B = 180-25.5-90

Angle B = 64.53665494

Hence, Angle B ≈ 64.5

Feel free to mark as brainliest

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Help me please<br><br><br><br> thanks so muchhhh
Leviafan [203]

Answer: 65 degrees

Step-by-step explanation:

If you learned angles, you would know that m∠2 and m∠6 are corresponding angles since it was already given that a║b.

Reasoning: m∠2=m∠6; if m∠2=65, then m∠6=65 as well.

Have a nice day! :D

6 0
3 years ago
HELP PLEASE!!!!!!!!​
Softa [21]

Answer:

I can't see the picture so can you pls write down the equation so i can solve it for you. Thank you bye!!!

Step-by-step explanation:

6 0
3 years ago
Perform the following calculations without rewriting the numbers in decimal form.
RSB [31]

Answer:

Answer will be 140\times 10^{13}

Step-by-step explanation:

We have to perform the calculation (1.42\times 10^{15}-2\times 10^{13}) without changing into decimal

1.42\times 10^{15} can be written as 142\times 10^{13}

So 1.42\times 10^{15}-2\times 10^{13}=(142\times 10^{13}-2\times 10^{13})

Now taking 10^{13} common

10^{13}(142-23)=140\times 10^{13}

6 0
3 years ago
Determine whether the pair of fractions is equivalent.
Margarita [4]

Answer:

yes, because they when divided by 2 they are the same

3 0
3 years ago
Read 2 more answers
You are rolling one die. Let event A = rolling a six and let event B = rolling a number less than
shtirl [24]

Answer:

2/3

Step-by-step explanation:

A = rolling a six

B = rolling a number less than 4

Probability of A or B

P(A) or P(B) = P(A) + P(B) - P(AnB)

Probability = (number of required outcome / Total possible outcomes)

P(A) = 1 / 6

P(B) :

Required outcomes = (3, 2, 1) = 3

P(B) = 3/6 = 1/2

P(AnB) = A={6} ; B = {1,2,3} ; AnB = {}

P(AnB) = 0

Hence,

P(A) or P(B) = 1/6 + 1/2 - 0

= (1 + 3) / 6

= 4/ 6

= 2/3

7 0
3 years ago
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