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bekas [8.4K]
3 years ago
11

Perform the following calculations without rewriting the numbers in decimal form.

Mathematics
1 answer:
RSB [31]3 years ago
6 0

Answer:

Answer will be 140\times 10^{13}

Step-by-step explanation:

We have to perform the calculation (1.42\times 10^{15}-2\times 10^{13}) without changing into decimal

1.42\times 10^{15} can be written as 142\times 10^{13}

So 1.42\times 10^{15}-2\times 10^{13}=(142\times 10^{13}-2\times 10^{13})

Now taking 10^{13} common

10^{13}(142-23)=140\times 10^{13}

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There are (713)3 ⋅ 70 strawberries in a field. What is the total number of strawberries in the field? (the 13 , 3 and 0 are expo
Fantom [35]
[(7**13)**3]*[7**0]

[7**39]*[1]..........>   9.0954 E 32 Strawberries in the field
6 0
3 years ago
If a person can see 6 miles from a height of 25 feet. How far can a person see from a height of 49 feet?
Bond [772]
11.79 miles see it’s .24 miles per foot .24x49=11.79
6 0
3 years ago
Ramen noodles. There are 20 ramen noodle packages in a bag. There are 10 beef flavored, and the other 10 are chicken flavored. W
Elina [12.6K]

Answer:

0.789

Step-by-step explanation:

Number of beef flavored Ramen noodles = 10

Number of chicken flavored Ramen noodles = 10

Total number of noodles = 20

Number of ways to select 3 packages:

_{20}C_3= \dfrac{20\times 19\times 18}{3\times 2\times 1}=1140

Number of ways to select two beef flavored Ramen noodle = _{10}C_2 = 45

Number of ways to select one chicken flavored Ramen noodle = 10

Number of ways to select two chicken flavored Ramen noodle = _{10}C_2 = 45

Number of ways to select one chicken flavored Ramen noodle = 10

Total number of ways so that one chicken and one beef Ramen selected = 450 + 450 = 900

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Required probability is:

\dfrac{900}{1140} = 0.789

8 0
3 years ago
Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0
1 year ago
4j + 4j − 6j − j = 12 <br> Solve for J
kherson [118]
J equals 12...........
3 0
3 years ago
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