Answer:
mass of 1 mole of H
2
=
3.4
g
+
O
2
=
10
g
→
H
2
O
=
3614.35999774
g
Explanation:
Answer:
51.84%
Explanation:
p² + 2pq + q² = 1 and p + q = 1
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
p = 0.72 => p² = 0.72² = 0.5184
=> Percentage of the rats are normal sized: 51.84%