Answer:
The answer is 1.4 miles ⇒ answer (d)
Step-by-step explanation:
* Let the balloon is at the vertex A, and the soccer fields
at vertex B and the football field at vertex C
∴ m∠B = 20° 15' = 20.25°
∴ m∠C = 62° 30' = 62.5°
∴ m∠A = 180 - 20.25 - 62.5 = 97.25°
∵ BC = 4 miles
* By using the sin Rule:
∵ AC/sin(B) = BC/sin(A)
∴ AC = (BC)(sinB)/sin(A)
∴ AC = [4 × sin(20.25)] ÷ sin(97.25) = 1.395 ≅ 1.4 miles
∴ The distance from the balloon to the football filed = 1.4 miles
The data is categorical data
Since the data is categorical data so it's become impossible to calculate either mean or median.
Now mode:
The data with the highest frequency is the mode.
So watchful is the mode because it contained 672 peoples
(x - 6) * 2
I'm assuming this is the expression that you typed out, if it isn't, please let me know in the comments :)
Use the distributive property:
= 2(x) - 2(6)
Multiply and simplify
= 2x - 12
This should be the expression that is equivalent to the original. Let me know if you need any clarifications, thanks!
