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Misha Larkins [42]
2 years ago
5

How many positive terms are in an arithmetic progression: 17.2; 17; 16.8

Mathematics
1 answer:
Fittoniya [83]2 years ago
7 0

Answer:

3

Step-by-step explanation:

a = first term = 17.2

tn = last term = 16.8

d= common difference = -0.2

n = number of terms = ?

To find the number of positive terms, we'll use the formula;

tn = a + (n - 1) d

Substituting the figures,

=> 16.8 = 17.2 + (n -1) -0.2

=> 16.8 - 17.2 = (n - 1) - 0.2

=> -0.4 = (n - 1) - 0.2

=> -0.4/-0.2 = n - 1

=> n - 1 = 2

=> n = 3

Therefore, the number of positive terms in the sequence is 3

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4. Write an equation for the line that is parallel to the given line and that passes
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Answer:

y=\frac{5}{2}x-14

Step-by-step explanation:

Hi there!

<u>What we need to know:</u>

  • Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)
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<u>1) Determine the slope (m)</u>

y=\frac{5}{2}x-10

In the given equation, \frac{5}{2} is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of \frac{5}{2}. Plug this into y=mx+b:

y=\frac{5}{2}x+b

<u>2) Determine the y-intercept (b)</u>

y=\frac{5}{2}x+b

Plug in the given point (-6,-29) and solve for b

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Simplify -6 and 2

-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b

Add 15 to both sides to isolate b

-29+15=-15+b+15\\-14=b

Therefore, the y-intercept is -14. Plug this back into y=\frac{5}{2}x+b:

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I hope this helps!

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