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katrin [286]
2 years ago
11

2x+5-x+10=1x-5+3x what does x=

Mathematics
1 answer:
NARA [144]2 years ago
8 0
The answer for x=20/3
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How do i graph the lines when the equations aren’t in slope intercept form????
jekas [21]

Slope-Intercept Form: y=mx+b

Standard Form: ax+by=c

Point- Slope: (y-y1)= m(x-x1)

There are multiple answers to your question-

  1. If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
  2. If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
  3. If you are given the standard form/point-slope form, change the equation to slope intercept form.
  4. If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.
7 0
3 years ago
This my test question I'm 100 bad at math 2b2+16b+49÷2b+4
krek1111 [17]
2b^2 + 81/2 b + 4 


basically 2b^2 + 16b + 49/2 b + 4 
= (2b^2) + 16b+49/2b) + (4) 
= 2b^2 + 81/2 b + 4 
5 0
3 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
1 year ago
Solve this equation: y-3x+15=10
Jlenok [28]

Answer:

10=10

Step-by-step explanation:

y-3x+15=10

y=3x-15+10

y=3x-5

subtitute y=3x-5 in the above equation:

3x-5-3x+15=10 (3x will be eliminated with -3x)

-5+15=10

10=10

(i hope this is the way you want the answer but at least I think it is correct)

3 0
3 years ago
Colin invests £4000 into his bank account. He receives 5% per year simple interest. How much will Colin have after 3 years? Give
MakcuM [25]

Answer:

2750

Step-by-step explanation:

7 0
2 years ago
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