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3 years ago

Graph the equation y= 1/2 + 4

1 answer:

8 0

I can’t really graph on this but place a dot on the four on the y axis and go up one and over two and place a dot there. just keep repeating it till u get to the end of the graph :)

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Find the additive inverse or _9.x + 3

Mekhanik [1.2K]

I’m really really sorry i can’t ask another question until i answer somebody’s questions.

6 0

2 years ago

How do you do x ^4-4? What is the x values?

VladimirAG [237]

We know that
A difference of two perfect squares (A² - B²) can be factored into (A+B) • (A-B)
 then
x ^4-4--------> (x²-2)*(x²+2)
(x²-2)--------> (x-√2)*(x+√2)
x1=+√2
x2=-√2

the other term
(x²+2)=0-> x²=-2-------------- x=(+-)√-2

i is called the imaginary unit. It satisfies i² =-1
Both i and -i are the square roots of -1
√ -2 =√ -1• 2 = √ -1 •√ 2 =i • √ 2 
The equation has no real solutions. It has 2 imaginary, or complex solutions.
x3= 0 + √2 i
x4= 0 - √2 i 

the answer is

the values of x are
x1=+√2
x2=-√2
x3= 0 + √2 i
x4= 0 - √2 i

3 0

3 years ago

What could I say for this question anybody who answers this gets brainlist Answer ASAP!

QveST [7]

Well simply just state ur learning goals are. In my opinion I would keep it short and simple but give a bit of detail to it. At most like 6 sentences should be ok and should work as an answer

7 0

2 years ago

If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?

Aleksandr [31]

Answer: 0.14

Step-by-step explanation:

Given: Mean : $\lambda=15\text{ per seconds}$

In minutes , Mean : $\lambda=4\text{ per minute}$

The exponential distribution function with parameter $\lambda$ is given by :-

$f(t)=\lambda e^{-\lambda t}, \text{ for }x\geq0$

The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-

$P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14$

Hence, the probability of waiting more than 30 seconds = 0.14

5 0

3 years ago

Will mark the Brainliest !!!!! A team of 5 boys and 4 girls will be chosen from a group of 16 boys and 13 girls,

vfiekz [6]

Answer:

Step-by-step explanation:

The total number of permutations of boys and girls on the team are:

¹⁶P₅*¹³P₄

Bob will be one of the fixed boys to be picked. Hence, actually 4 boys are to be picked from 15. The permutations of girls being picked remains the same.

Probability = Permutations with Bob as one of the boys / Total permutations

Probability = (¹⁵P₄*¹³P₄) / (¹⁶P₅*¹³P₄) = ¹⁵P₄ / ¹⁶P₅

Probability = $\frac{15!}{(15-4)!}/\frac{16!}{(16-5)!}$ = 15! / 16! = 1/16

Now, Bob is one of the fixed boys and Jane is one of the fixed girls. Hence, actually 4 boys are to be picked from 15 and 3 girls are to be picked from 12.

Probability = Permutations with bob as one of the boys and jane as one of the girls / Total permutations

Probability = (¹⁵P₄*¹²P₃) / (¹⁶P₅*¹³P₄) = (1/16)*(1/13) = 1/208

Now, the probability that at least Jane or Bob will be picked has been asked. This probability is a combination of three probabilities:

Probability = (Probability that only Bob will be picked) + (Probability that only Jane will be picked) + (Probability that both will be picked)

Probability = 1/16 + 1/13 + 1/208 = 0.123

Total teams possible = ¹⁶P₅*¹³P₄ = 8994585600 teams are possible

5 0

3 years ago

Graph the equation y= 1/2 + 4​

Graph the equation y= 1/2 + 4