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sweet [91]
2 years ago
15

Please help!! this is algebra 2​

Mathematics
1 answer:
sveta [45]2 years ago
3 0

Answer:  The last one bc it the same thing!

Step-by-step explanation: one 5/3 is the exact same as 5/3! and for the last one says -5/3

It would be the last one!

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Fifteen equals s over thirteen
zimovet [89]
Can you restate the question please
6 0
3 years ago
. Caroline had 400 stamps in her collection. 1 10 th of them were Indian stamps, Onethird of the remaining stamps were from Euro
Ganezh [65]

Answer:

So 400 stamps

African---> 100

Indian------> 1/10 x 400

= 40

European---> 400-40=360

1/3 x 360

= 120

so 120+40+100= 260

400-260

= 140 stams from US

6 0
3 years ago
Iris wants to buy sneakers at $15 each and high heels at $30 each. Write an algebraic expression to find the total cost of the s
kogti [31]

Answer: 30y + 15x

If x is for sneakers, and y is for high heels, plug 15 in for a and 30 in for b. This means that x is how many sneakers she buys, and y is how many high heels she buys. The equation altogether represents the total amount of her purchases.

5 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
Two groups went bowling. Here are the scores from each group.
vladimir2022 [97]

Answer:

Group A has greater variability

Step-by-step explanation:

Group A: 80, 100, 190, 110, 70, 90, 130

The variability of group A data :

Taking the range :

Maximum  = 190 ; Minimum = 70

Range = Maximum - Minimum ; 190 - 70 = 120

Group B : 50, 110, 100, 120, 107, 140, 150

The variability of group B data :

Taking the range :

Maximum  = 150 ; Minimum = 50

Range = Maximum - Minimum ; 150 - 50 = 100

Hence, Group A has greater variability

6 0
2 years ago
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