Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:
35/40 - 8/40 = 27/40.
I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)
When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:
27/40 * 1/5 = 27/200
So each piece is about 27/200 m in length (or 0.135 m in length).
If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
Answer:
I'm pretty sure that they are 4, 16, 64, and 256.
Step-by-step explanation:
There was an error in C.
<h3>What are helping verbs?</h3>
Whether they do so by conveying time, voice, possibility, necessity, obligation, or other crucial information, or by assisting in the framing of a question, supporting verbs provide additional information to the main verb. For the record, verbs are words that describe an action or state of being. Auxiliary verbs are another name for helping verbs (or auxiliaries). The most typical auxiliary verbs are, do, and have (in all of their forms), but there are also modal auxiliaries, commonly known as modals or modal verbs. In other words, while all auxiliary verbs are models, not all auxiliary verbs are helping verbs.
To learn more about Helping verbs, Visit:
brainly.com/question/14061315
#SPJ4
Answer:
A) 0.05
Step-by-step explanation:
Let's summarize into an equation the information we can get from that table.
We have 4 liters of an acid of an unknown concentration, let's call it (4x).
We have 10 liters of an acid with known concentration of 0.40.
And we have a total of 14 liters overall with a concentration of 0.3o.
That's like a weighted average formula: 4x + 10 y = 14z
Let's replace the concentration values we know and solve this:
4x + 10 (0.4) = 14 * 0.3
4x + 4 = 4.2
4x = 0.2
x = 0.05
So, the concentration of the 4 liters of acid on concentration X are in fact of concentration of 0.05.
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is 
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is 
. Thus, there are only 35 ways to distribute the blackboards in this case.
