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12345 [234]
3 years ago
11

The ratio of the cost of one metre of polyester fabric to the cost of one metre of cotton fabric is 2:7

Mathematics
1 answer:
yaroslaw [1]3 years ago
8 0

Answer:

The values of the table of costs in the explanation

Step-by-step explanation:

Let

x ---->the cost of one metre of polyester fabric

y ----> the cost of one metre of cotton fabric

we know that

The ratio of the cost of one metre of polyester fabric to the cost of one metre of cotton fabric is

\frac{x}{y}=\frac{2}{7}

Complete the table

Part 1) For 2 metres of fabric

To find out the costs multiply the ratio by the fraction 2/2

so

(\frac{2}{2})\frac{2}{7}=\frac{4}{14}

therefore

x=\£4\\y=\£14

Part 2) For 6 metres of fabric

To find out the costs multiply the ratio by the fraction 6/6

so

(\frac{6}{6})\frac{2}{7}=\frac{12}{42}

therefore

x=\£12\\y=\£42

Part 3) For 8 metres of fabric

To find out the costs multiply the ratio by the fraction 8/8

so

(\frac{8}{8})\frac{2}{7}=\frac{16}{56}

therefore

x=\£16\\y=\£56

Part 4) For 9 metres of fabric

To find out the costs multiply the ratio by the fraction 9/9

so

(\frac{9}{9})\frac{2}{7}=\frac{18}{63}

therefore

x=\£18\\y=\£63

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Temka [501]

Answer:

s(t) = -\dfrac{t^2}{160}+\dfrac{5}{8}t+20

Step-by-step explanation:

given,

initial price of buzz stock = $ 20 per share

after 20 days

stock price = $30 per share

after 40 days

the price =  $35 per share

let say it is modeled by

y = ax² + b x + c

x = number of days

y = stock price

x = 0 y = 20

20 = a x 0 + b x 0 + c

c = 20

x = 20 y = 30

30 = 20² a + 20 b + 20

400 a + 20 b = 10...........(1)

x = 40 y = 35

35 = 40² a + 40 b + 20

1600 a + 40 b = 15...........(2)

solving equation (1)and (2)

a = - 1/160

b = 5/8

y = -\dfrac{x^2}{160}+\dfrac{5}{8}x+20

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876.34 rounded to the nearest thousandth
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Answer:

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Step-by-step explanation:

You need another number after 4 to be able to round thousands

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

You can set up a system of equations for this problem. Let x = number of coach tickets and y = number of first class tickets. Then:

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Solve the second equation for y to get y = 17 - x, then plug that into the first equation and solve for x:

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