3 years ago

Cos(6x-12) = sin(8x-10)

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

7 0

Subtract sin (8x − 10) from both sides of the equation.

cos (6x − 12) − sin (8x − 10) = 0

vova2212 [387]3 years ago

6 0

Answer:

It doesn't exist

Step-by-step explanation:

since :

cos (90° – x) = sin x

cos(x) = sin(pi/2 - x)

then

cos(6x-12) =! sin(8x-10)

since (8x-10) =! (pi/2- 6+12)

then this identity of cos(6x-12) = sin(8x-10) doesn't exist

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Cos(6x-12) = sin(8x-10)​

Cos(6x-12) = sin(8x-10)