For this we will use kinematic equations.
We need the time of flight to compute the range.
With the given information, the most useful formula is:
Δy=v0yt−g2t2
Because our equation is taking only vertical motion into account,
v0y=30sin(45)
Because we are looking for the range of the object,
Δy=0
This leaves us with only one unknown: t
0=30sin(45)t−g2t2
g2t2=30sin(45)t
g2t=30sin(45)
t=60gsin(45)
For horizontal distance, the formula we need is:
Δx=v0xt
Because we are taking into account the horizontal range,
v0x=30cos(45)
In substituting our derived values into the equation we can see that:
Δx=30cos(45)∗60gsin(45)
Range=30cos(45)∗60gsin(45)
Newton’s first law of motion states that ever object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force is the definition of Newton’s first law of motion
Answer: C. A sense that the speaker feels out of place in 1950s America
Explanation:
D. get going
the sentence is in the past
Carl explained to Mark that he had some work to do and had to go.
Yes it’s true because of the size of the circle