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inna [77]
3 years ago
9

A play was attended by 348 people,some adults and some children. Admissions for adults was $1.50 and for children 75 cents. The

total amount collected was $390. How many adults attended the play?
Mathematics
1 answer:
natka813 [3]3 years ago
3 0

Answer:

172

Step-by-step explanation:

Let adults be x

and children be y

According to the problem,

x + y = 348              . . . (1)

1.5x + 0.75y = $390. . . (2)

From Eq 1, find the value of x:

x = 348 - y

Put this value in Eq 2:

1.5 ( 348 - y ) + 0.75y = 390

522 - 1.5y + 0.75 y = 390

-1.5y + 0.75y = 390 - 522

-0.75y = -132

y= -132/-0.75

y = 176

Put the value of y in Eq 1

x  + 176 = 348

x = 348 -1 176

x = 172

No. of children = 176

No. of adults = 172

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Step-by-step explanation:

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Step-by-step explanation:

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Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

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\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

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