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3 years ago

2x - 5y = - 15

Mathematics

2 answers:

RSB [31]3 years ago

8 0

Answer:

$y = \frac{2}{5} x + 3$

Step-by-step explanation:

2x - 5y = -15

Firstly, you will need to isolate the variable you are solving for, in this case, y.

2x - 2x - 5y = -15 - 2x

-5y = -15 - 2x

-5y/-5 = -15/-5 - 2x/-5

A negative divided or multiplied by a negative is positive.

$y = 3 + \frac{2}{5} x$

Rearrange.

$y = \frac{2}{5} x +3$

UkoKoshka [18]3 years ago

7 0

Answer:

2x+15=5y

y=(2x+15)/5

hope this helps

You might be interested in

The endpoints of the diameter of a circle are (−2, −3) and (4, −1). Which equation represents the circle?

Alika [10]

Answer:

The equation of circle is $(x-1)^{2}$ + $(y-2)^{2}$ = 18

Step-by-step explanation:

Given the endpoints of the diameter of a circle: (-2,-3) and (4,-1)

We know that the equation of circle is

$(x-h)^{2}$ + $(y-k)^{2}$ = $r^{2}$

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

( $\frac{x1+x2}{2}$ , $\frac{y1+y2}{2}$ )

( $\frac{-2+4}{2}$ , $\frac{-3-1}{2}$ )

(1,2)

Hence (h,k) is (1,2)

Substituting values of (h.k) and (x.y) as (1,2) and (4,-1) respectively in equation of circle, we get

$(4-1)^{2}$ + $(-1-2)^{2}$ = $r^{2}$

$r^{2}$ = 18

Now substituting values of (h,k) and $r^{2}$ in equation of circle, we get

$(x-1)^{2}$ + $(y-2)^{2}$ = 18

Hence the equation of circle is $(x-1)^{2}$ + $(y-2)^{2}$ = 18

5 0

3 years ago

Read 2 more answers

Help please !!!!!!!!!!!!!!

ohaa [14]

To start, we're given the range that x lies in: from -1 to 4. We know from the fact that $-1 \leq x$ that -1 will be included in that range, so we mark -1 on the number line with a solid circle. We also know from $x\ \textless \ 4$ that, while x can be any value up to 4, it does not include 4. We indicate this by drawing a hollow circle around 4 on the number line. Since x can be any value within this range, we make that fact clear by drawing a bold line between the points -1 and 4 on the number line. I've attached an image of what our final graph would look like.