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Salsk061 [2.6K]

3 years ago

8

7th grade math help me pleaseeee

2 answers:

lara [203]3 years ago

8 0

Ryan: y=10x+25 Alex: y=11x+20
a) Mr. Smith should choose Alex because the price would be $42 compared to Ryan which would be $45
b) Mr.Smith could choose either Ryan or Alex because they would both charge $75

tiny-mole [99]3 years ago

3 0

Answer:

the answer is 1-x5

Step-by-step explanation:

10x5 6x7+92 j0ll

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What is the answer for 44/p= 11/5 p=_____

Alex73 [517]

The answer to your question is p=20

4 0

3 years ago

X - 35 > 15 i need answer IMEDIATLEY

SIZIF [17.4K]

I'm assuming you want us to solve this inequality for x, since the question wasn't too clear on that.

$x - 35 > 15$

Add 35 to both sides to remove the "-35" on the left side so we can isolate the x

$x-35+35>15+35$

$x>50$

The solution to this inequality is x>50. Let me know if you need any clarifications, thanks!

~ Padoru

6 0

3 years ago

Lim x-27/x¹/³-3 x->3 please can I get quick solution to this,please help me out.

marin [14]

Answer:

which math is this? what is it asking u to do

6 0

4 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

3 years ago

There is a bag filled with 5 blue and 4 red marbles.

PtichkaEL [24]

Answer:

<h2>8/9</h2>

Step-by-step explanation:

9 in total 4 blue

4/9 x 2

8/9

5 0

2 years ago