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3 years ago

7th grade math help me pleaseeee

Mathematics

2 answers:

lara [203]3 years ago

8 0

Ryan: y=10x+25 Alex: y=11x+20
a) Mr. Smith should choose Alex because the price would be $42 compared to Ryan which would be $45
b) Mr.Smith could choose either Ryan or Alex because they would both charge $75

tiny-mole [99]3 years ago

3 0

Answer:

the answer is 1-x5

Step-by-step explanation:

10x5 6x7+92 j0ll

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3 years ago

X/6 = 10/9<br> improper fraction in its simplified form

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3 years ago

Jan and Col club together a book of raffle tickets. They agree to share any prize they win in the ratio 2:3. When they win Jan g

nikitadnepr [17]

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2 years ago

Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a

Vikki [24]

Answer:

$0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730$

$0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890$

And the confidence interval would be:

$0.730 \leq \p \leq 0.890$

Step-by-step explanation:

Information given:

$n=131$ represent the sample size

$\hat p=0.81$ represent the estimated proportion

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.326$

And replacing into the confidence interval formula we got:

$0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730$

$0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890$

And the confidence interval would be:

$0.730 \leq \p \leq 0.890$

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3 years ago