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4 years ago

Give one example of when you would use the friendly numbers stratety to subtract. Explain why.

Mathematics

1 answer:

Nezavi [6.7K]4 years ago

6 0

U should use friendly numbers when subtracting.......the numbers have to be between 3 and 10

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Please help me with this.... 4x+3=23

MArishka [77]

Answer:

x=5

Step-by-step explanation:

23-3= 4x or 20

that means 4x is equal to 20

20 divided by 4 is 5

so x is equal to 5

6 0

3 years ago

Can i get some help on this question?

galben [10]

Answer:

a. 12.5

Step-by-step explanation:

Scale factor of ∆LMN to ∆XYZ = 2:5

To find length of side ZX, set the ratio of the corresponding sides of interest equal to the scale factor.

Thus:

ZX corresponds to NL = 5

NL:ZX = 2:5

5:ZX = 2:5

5/ZX = 2/5

Cross multiply

5*5 = ZX*2

25 = ZX*2

Divide both sides by 2

25/2 = ZX

12.5 = ZX

ZX = 12.5

4 0

3 years ago

If A=(0,0) and B=(8,2), what is the length of AB

NeX [460]

Answer:

$\boxed{\sf Distance_{AB}= 8.24 \ units }$

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , A(0,0) and B(8,2) . The distance between the two points can be found out using the Distance Formula , which is ,

Distance Formula:-

$\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}$

Therefore on substituting the respective values ,we can find the Distance as ,

$\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}$

Simplify the brackets ,

$\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}$

Square the numbers inside the squareroot ,

$\sf\longrightarrow Distance =\sqrt{ 64 + 4}$

Add the numbers inside the squareroot ,

$\sf\longrightarrow Distance = \sqrt{68}$

Find the value of squareroot,

$\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}$

Hence the distance between the two points is 8.24 units .

3 0

3 years ago

Round the value 44.981 to three significant figure

Bas_tet [7]

Answer:

45.0

Step-by-step explanation:

44.981 = 45.0 (to 3 s.f.)

*important point to note: the 0 must be included as the question asked for 3 significant figures. In this case, 0 is significant.

I hope this helps :)

8 0

3 years ago

Amanda's school is due west of her house and due south of her friend Shereen's house. The distance between the school and Sheree

Blizzard [7]

The Amanda's house is 6.7 km far from her school.

Step-by-step explanation:

From the given information,

The Amanda's school is due west of her house forms the base.
The school is due south of the Shereen's house forms the height.
The straight-line distance between Amanda's house and Shereen's house forms the hypotenuse.

Therefore, It can be determined that it forms the right angle triangle.

It is given that,

The distance between the school and Shereen's house is 2 kilometers.

That is, the height of the triangle = 2 km

The straight-line distance between Amanda's house and Shereen's house is 7 kilometers.

That is, the hypotenuse of the triangle = 7 km

Now, the distance between the Amanda's house and her school is the base of the triangle.

To find the base :

Base = $\sqrt{(hypotenuse)^{2}-(height)^{2} }$