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2 years ago

PLEASE I NEED HELP! I need to find the value of X rounded to the nearest tenth

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

8 0

65 x 11 I have 2m and a few other people that are not interested to see if they can easily get the best of their time and will

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Estimate the answer to<br> 64 x 186<br> 21 x 98

Vikentia [17]

Answer:

I am a bit confused on what the question is asking. But 64*186= 11904 and if we were to round that number it would be 12000. 21*98=2058 and that number rounded is 2100 or just 2000. (hope this is right and helps :D)

Step-by-step explanation:

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3 years ago

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A Ms. Carter cut 1,874 strips of paper for a craft project she is doing with a group of students. If there are 8 students in the

Mars2501 [29]

Answer:

We are multiplying.

Step-by-step explanation:

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2 years ago

What is the y-intercept of the graph of the equation 6x-5y=-15

guapka [62]

Answer:

y-intercept = 3

Step-by-step explanation:

The given equation is :

6x-5y=-15

We can rewrite it ib slope-intercept form as follows :

Dividing both sides by 5

$\dfrac{6x}{5}-y=\dfrac{-15}{5}\\\\\dfrac{6x}{5}-y=-3\\\\\dfrac{6x}{5}+3=y$ .....(1)

The general equation of slope-intercept form is:

y = mx +c ....(2)

On comparing equation (1) and (2) we get :

m = 6/5

c = 3

Hence, the y intercept of the graph of the equation is 3.

7 0

3 years ago

Nevermind, the question has been solved.

san4es73 [151]

okay.... I guess??? lol

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3 years ago

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

2 years ago

￼PLEASE I NEED HELP! I need to find the value of X rounded to the nearest tenth

PLEASE I NEED HELP! I need to find the value of X rounded to the nearest tenth