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2 years ago

PLEASE HELP !!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!

Mathematics

1 answer:

Alona [7]2 years ago

7 0

Answer:

77-55=22, i don't know if this is the answer if i'm wrong sorry im just trying to help you.For every 22 followers tyler has, Naomi has 22 leser followers

Step-by-step explanation:

IF i am right pls subscribe to Amiredagoat Yt

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Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!

MArishka [77]

Answer:

- 18y = 1

Step-by-step explanation:

Adding the 2 equations term by term on both sides gives

(- 5x + 5x) + (- 9y - 9y) = (3 - 2), that is

0 + (- 18y) = 1

- 18y = 1

7 0

2 years ago

Which of the following statements it’s true?

guapka [62]

Answer:

Step-by-step explanation:

7 0

3 years ago

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The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

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Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is <em>True.</em>

7 0

2 years ago

PLEASE I REALLY NEED HELP

vovangra [49]

Answer:

who think

Step-by-step explanation:

5 0

2 years ago

$18.99 with the discount of 30% off

ASHA 777 [7]

So you would do .30 multiply that by 18.99 and your answer would be 5.69

6 0

2 years ago

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