What's the answer to that question
2 answers:
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Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
so we have a 60-30-90 triangle (top one)
so since we know 6 is x (the side on the right angle and 60 degrees)
b is 2x or 2(6) = 12
a is x√3 = 6√3
for C I need to use a 45 45 90 triangle
Since b is 12 and its x√2 to find x we should write it as
x√2 = 12
√2 √2 divide by √2
x = 12/√2 but we must rationalize the denominator
12/√2 times √2/√2 = 12√2/2 and that's c
Answer:
<h2>Midpoint (1 , 5)</h2>Step-by-step explanation:
Let (x , y) be the coordinates of the midpoint then: