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Sonja [21]
3 years ago
11

Need help plsssssssss

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0
Sheeeeeeesssshhhhhhh
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siniylev [52]
Hopefully this helps, and sorry I didn't do 8 I'm limited on time

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Write an expression for the sequence of operations described below.
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(h+g)=n➗2 is the answer. happy to help you

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Match the three graphs to the function they represent ?
Mama L [17]

Suppose that a>b>1, then

a^x>b^x and \log_ax

Therefore, since 2<3<7, \log_2x>\log_3x>\log_7x.

Choose an arbitrary x>1. You have that a takes the greatest values at x, c takes the smallest value at x. Thus,

a>b>c and

  • a=\log_2x;
  • b=\log_3x;
  • c=\log_7x.

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Por que es importante que los científicos desarrollen una forma de hacer los tejidos que se han construido en el sistema de sumi
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4 years ago
Find a solution to the linear equation −2x−2y=8 by filling in the boxes with a valid value of x and y.Provide your answer below:
inna [77]

Given

-2x-2y=8

To find a solution for the linear equation, the first step is to write the equation in slope-intercept form:

-Pass the x-term to the right side of the equation by applying the opposite operation to both sides of the equal sign:

\begin{gathered} -2x+2x-2y=8+2x \\ -2y=2x+8 \end{gathered}

-Divide both sides by -2:

\begin{gathered} \frac{-2y}{-2}=\frac{2x}{-2}+\frac{8}{-2} \\ y=-x-4 \end{gathered}

Once you have expressed the equation of the line in slope-intercept form, replace it with any value for x and calculate the corresponding value of y, for example, x=2

\begin{gathered} y=-(2)-4 \\ y=-2-4 \\ y=-6 \end{gathered}

One solution for the linear equation is x=2 and y=-6, you can check the solution by replacing the values on the original equation, with both values the result should be 8:

\begin{gathered} -2x-2y \\ -2\cdot2-2\cdot(-6) \\ -4+12=8 \end{gathered}

As you can see the values are a valid solution for the linear equation.

So the solution is:

-2(2)-2(-6)=8

6 0
1 year ago
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