Answer:
BZ = 64/23 = 2 18/23
Step-by-step explanation:
The angle bisectors divide the triangle into proportional parts, so we have ...
CB/CY = AB/AY
CB = CY(AB/AY) = 4(8/6) = 16/3 . . . . multiply by CY and evaluate
and ...
BZ/CB = AZ/AC
BZ = AZ(CB/AC) . . . . multiply by CB
But we have ...
AZ = 8 -BZ, so this becomes ...
BZ = (8 -BZ)(16/3)/(10)
BZ(1 +8/15) = 64/15 . . . . add the BZ term on the right to both sides
BZ = (64/15)(15/23) = 64/23 . . . . divide by the coefficient of BZ
BZ = 64/23 = 2 18/23
are angle bisectors of triangle ABC that meet at I as shown below, with CY = 4, AY = 6, and AB = 8. Find BZ.
