The answer 1500 hope it helped
1/64
Your square will be (x - 1/8)^2 which evaluates to x^2 - 1/4x + 1/64.
Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
Answer:
Step-by-step explanation:
Let's FOIL out both sides and then see where we are after that:
Let's combine like terms now and get everything on one side of the equals sign and set the polynomial equal to 0 to solve for x:
0 = 8x - 4 and we can factor out a 4 to give us:
0 = 4(2x - 1)
Either 4 = 0 or 2x - 1 = 0. Well it's obvious that 4 does not equal 0, so 2x-1 must equal 0. Then
2x = 1 so
x = 1/2 or choice A on the left.
Answer:
3??
Step-by-step explanation:
im trying, sorry if its wrong :(
