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Natalka [10]
3 years ago
7

What is the value of n? Write your answer as a number only

Mathematics
1 answer:
GalinKa [24]3 years ago
5 0

Answer:

45

Step-by-step explanation:

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Jessica knows that the adult population gets, on average, eight hours of sleep each night. A hypothesis test can help her see if
Nitella [24]

Answer:

-4.42

Step-by-step explanation:

Given the following :

Population mean (pm) = 8 hours

Sample mean (sm) = 6.9 hours

Number of observations (n) = 101 students

Sample standard deviation (sd) = 2.5

Using the t-statistic formula :

[(sm - pm) / (sd/√n)]

Hence,

[(6.9 - 8) / (2.5/√101)]

[(-1.1) / (2.5/10.05)]

-1.1 / 0.2487562

= −4.422

The test statistic = - 4.42 to the nearest hundredth.

6 0
3 years ago
You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads
tino4ka555 [31]

P(2 or H) = P(2) + P(H) - P(2 and H)  

What is the probability of getting a 2 P(2)?  = 1/6

What is the probability of getting heads P(H)?  = 1/2

P(2 and H) is the product of those two events since the events are independent. = 1/6 * 1/2 = 1/12

P(2 or H) = P(2) + P(H) - P(2 and H)  

P(2 or H) = 1/6 + 1/2  - 1/12 = 7/12

5 0
3 years ago
What is the answer to F(-2) =
Fofino [41]

Just substitute - 2 into x and solve.

7 0
3 years ago
What is the area of a circle with radius of 1 foot
kozerog [31]

Answer:

pift^2(or your third option) is the area of a circle with a radius of 1.

7 0
3 years ago
Read 2 more answers
An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that \pi = 0.2

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}

0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}

\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}

(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}

n = 5615

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now \pi = 0.12, n = 5615.

We have to find M.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 2.81\sqrt{\frac{0.12*0.88}{5615}}

M = 0.012

7 0
2 years ago
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