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slavikrds [6]
2 years ago
15

QUESTION 2

Mathematics
1 answer:
gregori [183]2 years ago
3 0

Answer:

Step-by-step explanation:

ppleasepplease share the answers when got them

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Find the value of x 55+(x+25)=180
s344n2d4d5 [400]
55+(x+25)=180
55+x+25=180
25+55+x=180
80+x=180
x=180-80
x=100
5 0
3 years ago
If x varies directly with y and y is 10 when x is 8, what is x when y is 18?
swat32
Knowing that x varies directly with y, we know the basic skeleton of the equation is y = mx. 

To find m, plug in the known coordinate (8,10), where the x-coordinate is 8 and the y-coordinate is 10.
y=mx \\ 10=m8 \\ (10)/8=(8m)/8 \\ m= \frac{10}{8} = \frac{5}{4}

Then, plug in m to the equation to get y = (5/4)x.

Finally, plug in the y-coordinate 18 to the equation and solve for x!
y= \frac{5}{4}x \\ 18= \frac{5}{4}x \\  \frac{4}{5}(18)=( \frac{5}{4}x) \frac{4}{5} \\ x= \frac{4*18}{5}  \\  x= \frac{72}{5}

Your exact answer is x = 72/5. However, if your teacher prefers decimals, then x = 14.4

Hope this helps!
5 0
3 years ago
Read 2 more answers
X + y = 4<br> 3x + 4y= 14
Vaselesa [24]
Y = 4 - x
3x + 4(4-x) = 14
3x + 16 -4x = 14
-x = -2
x = 2
y = 2
7 0
3 years ago
Read 2 more answers
You are taking a trip at the same time as another
Valentin [98]

Answer:

My family is traveling faster, since it is traveling at the rate of 950 miles per day, while the other family travels at 900 miles per day.

Step-by-step explanation:

Since I am taking a trip at the same time as another family, and my family traveled 1,900 miles in 2 days, while their family traveled 2,700 miles in 3 days, to determine who is traveling faster the following calculation must be performed:

1,900 / 2 = 950

2,700 / 3 = 900

Thus, my family is traveling faster, since it is traveling at the rate of 950 miles per day, while the other family travels at 900 miles per day.

4 0
3 years ago
para preparar 10 litros de pintura naranja se necesitan 6 litros de pintura amarilla y 4 litros de pintura roja que cantidad de
nikdorinn [45]
Someone translate please
8 0
2 years ago
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