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bagirrra123 [75]
3 years ago
6

Scientists found that a certain particle of dust doubles every 30 minutes. If the scientists tests this out with 21 grams of the

specific dust, how many grams would they have after 2 days?
Mathematics
1 answer:
monitta3 years ago
7 0

Answer: 1.663\times 10^{30}\ gm

Step-by-step explanation:

Given

Population of dust particle doubles every 30 minutes

If the initial sample is 21 grams

The model to predict the population will be

\Rightarrow P=21\cdot 2^{2t}

Where t=time in hours

A day has 24 hours . So, for 2 days time is 48 hours

Population is given by

\Rightarrow P=21\cdot 2^{2\times 48}\\\\\Rightarrow P=21\times 2^{96}\\\\\Rightarrow P=1.663\times 10^{30}\ gm

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Step-by-step explanation:

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3 years ago
MN0 with vertices M(4,-5), N(5,-8), O(8, -6) ; translate the new figure M'N'O' (-2,5)
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5 0
3 years ago
WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i
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Answer:

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

z=r(\cos \theta +i\sin \theta)

where, r=\sqrt{a^2+b^2} and \tan \theta=\dfrac{b}{a}, \theta is called the argument of z, 0\leq \theta\leq 2\pi.

The given complex number is -5i.

It can be rewritten as

z=0-5i

Here, a=0 and b=-5. \theta lies in 4th quadrant.

r=\sqrt{0^2+(-5)^2}=5

\tan \theta=\dfrac{-5}{0}

\tan \theta=\infty

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\theta=\dfrac{3\pi}{2}

So, the trigonometric form is

z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)

4 0
3 years ago
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3 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

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P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

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The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

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