Okay so you split 9ab + 12ax - 6b - 8x
<span> into two 2-term polynomials </span>
+ 12ax + 9ab and - 6b - 8x
doesn't look that good to me so lest try other one :
9ab + 12ax and - 6b - 8x
looks good for now
<span> </span> Pull out from each binomial separately
9ab + 12ax = 3a • (3b + 4x)
- 6b - 8x = - 2 • (3b + 4x)
<span> </span> Add up to arrive at the desired factorization so now you have
<span> (3a - 2) • (3b + 4x)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope that Helped!</span>
Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).
Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²
Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3
Answer:
Answer:
22.5
Step-by-step explanation:
You subtract 3 from both sides and then divide 2 from both sides which should look like this
3(2x)=48
-3 -3
2x=45
-:- 2
x=22.5
Answer:
Area formula=b*h÷2
b=a÷h*2
b=12
Step-by-step explanation:
So if you multiply the base and height to find a triangle, you'd get the area of a rectangle instead so if you divide by 2, you'd get the area of a triangle
To find the base, you'd reverse the process. You'd divide the area by the height and multiply by 2.
36÷6=6
6*2=12
Hope that helps!
Answer:
The interquartile range is the difference between the highest and lowest values in the middle of a data set.
Step-by-step explanation:
The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.
The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.
The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.
