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lutik1710 [3]
3 years ago
13

Given f(x) = 3x - 1 and g(x)= -x + 6, find f(-2) + g(5). A.-6 B.6 C.8

Mathematics
1 answer:
vladimir2022 [97]3 years ago
3 0
Find what f(x) is when x = -2
3(-2) - 1 = -7
Find g(x) when x = 5
-(5) + 6 = 1
Add -7 + 1
-7 + 1 = -6
Option A)
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Q # 8 please helme to resolve
kondor19780726 [428]

Sequence 1,5,9,13,...

A(0) = 1 +4x0=1

A(1) =1 + 4x1 = 5

A(2) = 1+ 4x2= 9

A(3) = 1 +4x3=13

A(n)= 1+4n   A(n-1) = 1+4(n-1) =1+4n-4= - 3+4n

A(n) - A(n-1) = (1+4n) - (-3=4n) = 4

A(n) = A(n-1) +4; 29 is the answer

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What is a geometric sequence and arithmetic sequence?<br><br> ~MUST EXPLAIN~
Vadim26 [7]
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An arithmetic sequence is one that involves multiplication or division. For example, "Jon receives 5 dollars each week. If he waits for 5 months, how much money will he have? Honestly, all you have to do is think about the formula. x * 5. x would be the number of weeks. 

I know my answer is not as good as the verified one, but it is simpler and easier to understand. I apologize if it isn't good enough. 
6 0
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adell [148]

9514 1404 393

Answer:

  equation: y = 4x

  graph is attached

Step-by-step explanation:

Let y represent the cost of the peaches in dollars. Let x represent their weight in pounds. Then the relation between the two variables is ...

  cost = (cost per pound) × (pounds)

  y = 4x

__

This graphs as a line through the origin with a slope of 4. In the attached, the x- and y-axes have different scales so more of the graph can be seen.

8 0
3 years ago
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Gala2k [10]
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6 0
3 years ago
3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls
tatuchka [14]

Answer:

x=\frac{13}{2}, y=\frac{51}{4}

Step-by-step explanation:

We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}

Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}

4 0
3 years ago
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