All categories

2 years ago

Solve this .....................

Mathematics

1 answer:

ycow [4]2 years ago

5 0

Answer:

Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0

3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]

28x root5 = 10 root5 [ -10root5 turns to 10 root5 when transferred to RHS]

28x root 5/root5 =10

28x=10

x = 10/28

x = 0.35

Hope it helped u,

pls mark as the brainliest

^v^

You might be interested in

michael rented a truck for one day. there was a base fee of $20.95 , and there was an additional charge of 93 cents for each mil

jonny [76]

Let x = number of miles, cost per mile = 93 cents = $0.93

Cost = 20.95 + 0.93*x

200.44 = 20.95 + 0.93x

0.93x + 20.95 = 200.44

0.93x = 200.44 - 20.95

0.93x = 179.49

x = 179.49/0.93

x = 193

He drove 193 miles.

6 0

2 years ago

cylinder a has a radius of 1 m and a height of 4 m cylinder b has a radius of 1 m and a height of 8 what is the ratio of the vol

ikadub [295]

Volume of A= πR².H ==> V(A)=4π m³

Volume of V =πR².H ==>V(B)=8π m³

.Ratio of A to B =(4π) /(4π) = 1/2

8 0

2 years ago

Read 2 more answers

Plzzzzz someone help me

solong [7]

The answer is The equation 3.5|6x – 2| = 3.5 has one solution

4 0

2 years ago

Read 2 more answers

Express the function h(x)=(x+4)^5 in the form of f of g ( f o g). If f(x)=x^5 , find the function of g(x).

Bess [88]

Answer:

I DONT KNOW DO YOU WANT TO BE MY FRIEND

Step-by-step explanation:

3 0

2 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line.? y = 2 + se

sertanlavr [38]

Answer:

The volume of the solid is: $\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

Step-by-step explanation:

GIven that :

$y = 2 + sec \ x , -\dfrac{\pi}{3} \leq x \leq \dfrac{\pi}{3} \\ \\ y = 4\\ \\ about \ y \ = 2$

This implies that the distance between the x-axis and the axis of the rotation = 2 units

The distance between the x-axis and the inner ring is r = (2+sec x) -2

Let R be the outer radius and r be the inner radius

By integration; the volume of the of the solid can be calculated as follows:

$V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(4-2)^2 - (2+ sec \ x -2)^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [(2)^2 - (sec \ x )^2]dx \\ \\ \\ V = \pi \int\limits^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} [4 - sec^2 \ x ]dx$

$V = \pi [4x - tan \ x]^{\dfrac{\pi}{3}}_{\dfrac{-\pi}{3}} \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) - 4(-\dfrac{\pi}{3})+ tan (-\dfrac{\pi}{3})] \\ \\ \\ V = \pi [4(\dfrac{\pi}{3}) - tan (\dfrac{\pi}{3}) + 4(\dfrac{\pi}{3})- tan (\dfrac{\pi}{3})] \\ \\ \\ V = \pi [8(\dfrac{\pi}{3}) - 2 \ tan (\dfrac{\pi}{3}) ]$

$\mathbf{V = \pi [ \dfrac{8 \pi}{3} - 2\sqrt{3}]}$

7 0

2 years ago

Solve this .....................​

Solve this .....................