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3 years ago

8

Pls help, I don't understand

1 answer:

Ne4ueva [31]3 years ago

5 0

1 Yes 2. Yes

Step-by-step explanation:

they are similar because in problem one each side is related by a factor of 3

in problem 2 each side is related by a factor of 2.

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What is the answer so I could get the question

qaws [65]

Answer:My answer is Temp-pH I

I don't know if it is right or not

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3 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

PLEASE READ! HELPFUL INFORMATION

Volgvan

Answer:

u kind of forgot the attachment bestie

7 0

2 years ago

All rhombuses are parallelograms, but not all parallelograms are rhombuses. What attribute does a rhombus have that a parallelog

spin [16.1K]

C. 2 sets of opposite congruent angles

3 0

3 years ago

Read 2 more answers

PLEASE HELP FASTTTTTT IT IS DUE SOON thank you!

lions [1.4K]

Answer:

The answer to both photos is 1.

Step-by-step explanation:

Rise over run is looking at each plotted point on the graph and counting upward until level with the first point from zero, then going across the graph until you reach the plotted point.

The rise for the first picture is 3/1, and if you reverse them, you get, (1, 3).

- Hope this helps, good luck.

5 0

3 years ago