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3 years ago

What is the slope of a line perpendicular to the line whose equation is x−2y=12.

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

-2/x

Step-by-step explanation:

simplified is y = -x/2 - 6

Perpendicular slopes are just reciprocals of the original slope, so just flipp the original slope around to be the complete opposite.

Example if slope= -2, the reciprocal= -1/2

Just flip the numerator with the denominator for perpendicular slope

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A restaurant served 27,500 customers in 2012. In 2014, the restaurant served 29,000 customers. Write a linear model that represe

rjkz [21]

Answer:

In 2012, a restaurant served 27,500 customers and in 2014, the restaurant served 29,000 customers.

First determine the increase in the number of customer served each year.

the number of customer increase in each year is, $\frac{29000-27500}{2} =\frac{1500}{2} =750$

therefore, the linear model is;

y = 750x+ 27500 , where y represents the number of customers that the restaurant serves x years after 2012.

Now, to predict the number of customers that the restaurant will serve in 2020 is;

since, x = 2020-2012 = 8 years

$y = 750 \times 8 +27500$ or

$y= 6000+27500=33,500$

therefore, the number of customers that the restaurant will serve in 2020 = 33,500

3 0

3 years ago

I cant seem to figure out this question? someone please help me please

Brilliant_brown [7]

h is measured in miles so you need to convert 1135ft to miles

1 mile = 5280 feet

so 1135/5280 = 0.21496 miles

D = sqrt(2(3960)(0.21496) + 0.21496^2)

D = sqrt(1702.4832 + 0.046207801)

D = sqrt(1702.529408

D = 41.2617 miles round answer as needed

5 0

3 years ago

What's the answer to 243.875 to nearest tenth,hundredth, ten,and hundred

trapecia [35]

Tenth: 243.9
Hundredth: 243.88
Ten: 240
Hundred: 200

3 0

3 years ago

Read 2 more answers

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

3 years ago

Evaluate the expression : common log of square root 9/25.

tekilochka [14]

You want log √(9/25). Recognizing that √9 = 3 and that √25 = 5, we get

log 3/5, which by rules of logs comes out to log 3 - log 5.

To four decimal places:

log 3 - log 5 = 0.4771 - 0.6990, or -0.2218.

4 0

3 years ago