A) Using the special right triangle ratio for 30-60-90 triangles (which is 1-√3-2, opposite sides of the angles respectively, we can find that the side opposite the sixty degree angle is 41√3.
b) The hypotenuse is the same. Using the ratios, we see that the hypotenuse is 82.
c)sin(30)= opp/hyp = 41/82 = 1/2
cos(30)= adj/hyp = 41√3/82 = √3/2
tan(30)= opp/adj = 41/41√3 = 1/√3 = √3/3
Answer:
The sequence of first five terms
4 , 5, 6, 7, 8
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given
of the sequence
aₙ = n + 3 ..(i)
put n =1
a₁ = 1 +3
a₁ = 4
The first term of the sequence = 4
Put n =2 in equation (i)
a₂ = 2+3
a₂ = 5
The second term of the sequence = 5
put n=3 in equation (i)
a₃ = 3+3 = 6
The third term of the sequence = 6
Put n=4 in equation (i)
a₄ = 4 +3
a₄ = 7
The fourth term of the sequence = 7
Put n = 5 in equation (i)
a₅ = 5+3
a₅ = 8
The fifth term of the sequence = 8
<u><em>Step(ii):-</em></u>
The sequence of first five terms
4 , 5, 6, 7, 8
Answer:
172 ft
Step-by-step explanation:
120 + the other 1/4 is 160 160 + 12 is 172
Answer:
a) 17.09 hours
b) The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 49 - 1 = 48
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 48 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0106
The margin of error is:
M = T*s = 2.0106*8.5 = 17.09
s is the standard deviation of the sample. 17.09 hours is the answer for a.
The lower end of the interval is the sample mean subtracted by M. So it is 49 - 17.09 = 31.91 hours
The upper end of the interval is the sample mean added to M. So it is 49 + 17.09 = 66.09 hours
The 95% confidence interval estimate of the population mean flying time for the Pilots is between 31.91 hours and 66.09 hours