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3 years ago

Which is true regarding pseudocode?

Computers and Technology

2 answers:

bearhunter [10]3 years ago

8 0

Answer:

It uses simple words and symbols to communicate the design of a program

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications. There are seven (7) main stages in the creation of a software and these are;

1. Planning.

2. Analysis.

3. Design.

4. Development (coding).

5. Testing.

6. Implementation and execution.

7. Maintenance.

A pseudocode refers to the description of the steps contained in an algorithm using a plain or natural language. Also, a pseudocode gives a summary of the steps adopted during a software development process using simple (concise) words and symbols.

This ultimately implies that, a pseudocode uses simple words and symbols to communicate the design of a program.

Furkat [3]3 years ago

6 0

Answer:

A: It uses simple words and symbols to communicate the design of a program

Explanation:

Credit to the person above me.

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Naddik [55]

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3 years ago

The Monte Carlo method is commonly used to approximate areas or volumes of shapes. In this problem, we will use Monte Carlo to f

sdas [7]

Answer:

import numpy as np

import matplotlib.pyplot as plt

def calculate_pi(x,y):

points_in_circle=0

for i in range(len(x)):

if np.sqrt(x[i]**2+y[i]**2)<=1:

points_in_circle+=1

pi_value=4*points_in_circle/len(x)

return pi_value

length=np.power(10,6)

x=np.random.rand(length)

y=np.random.rand(length)

pi=np.zeros(7)

sample_size=np.zeros(7)

for i in range(len(pi)):

xs=x[:np.power(10,i)]

ys=y[:np.power(10,i)]

sample_size[i]=len(xs)

pi_value=calculate_pi(xs,ys)

pi[i]=pi_value

print("The value of pi at different sample size is")

print(pi)

plt.plot(sample_size,np.abs(pi-np.pi))

plt.xscale('log')

plt.yscale('log')

plt.xlabel('sample size')

plt.ylabel('absolute error')

plt.title('Error Vs Sample Size')

plt.show()

Explanation:

The python program gets the sample size of circles and the areas and returns a plot of one against the other as a line plot. The numpy package is used to mathematically create the circle samples as a series of random numbers while matplotlib's pyplot is used to plot for the visual statistics of the features of the samples.

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3 years ago

CIST 1122 Project 2 Instructions

NikAS [45]

Answer:

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Explanation:

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3 years ago

Given that Jamie worked 50 hours (Hours = 50) last week and earns $10.00 an hour (Rate = 10), how much did Jamie earn last week,

quester [9]

Answer:

Jamie earned (Total pay) $500.

Explanation:

We are given the following code:

If (Rate >=10) OR (Hours <=40) Then

TotalPay = Hours * Rate

Else

TotalPay = (Hours * Rate)+(Hours–40)*Rate*1.5

End If

Let us understand the code line by line:

The first line contains an if statement with 2 conditions:

i.e. 1st condition:

The rate is greater than or equal to 10

2nd condition:

Number of hours are lesser than or equal to 40.

There is OR between the two condition i.e. the statement next to if() statement will get executed if any one of them becomes true and else part will not be executed.

The next statement is:

TotalPay = Hours * Rate

It calculates the pay if any of the two conditions written earlier becomes true.

Next statement is else statement:

It will get executed given that the above if() statement becomes false.

Now, we are given that Jamie worked 50 hours last week and earns $10.00 an hour:

i.e.

Hours = 50

Rate = 10

Now, let get to the code execution.

The first condition is true i.e. Rate >= 10 (because Rate is 10 here)

So, the following statement will be used to calculate the Total pay:

TotalPay = Hours * Rate

and else part will not be executed.

TotalPay = 50 * 10 = $500

Jamie earned (Total pay) $500.

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Step2247 [10]

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3 years ago