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Ostrovityanka [42]
2 years ago
8

If r is an odd integer and m=8r then m/2 will always be

Mathematics
1 answer:
kogti [31]2 years ago
3 0

Answer:

b. even

Step-by-step explanation:

m is a multiple of 8, so it is also a multiple of 4.  When a multiple of 4 is divided by 2, the result is a multiple of 2 (even).

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Last year there were 120 students in choir. This year, 30% more students took choir. How many students are taking choir this yea
soldi70 [24.7K]

Answer:

156 students

Step-by-step explanation:

To find how many students are in choir this year, multiply 120 by 1.3

120(1.3)

= 156

So, this year, 156 students are taking choir

7 0
3 years ago
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In a seminar of 1200 people, 65 percent were women, How many men were in the seminar?
Nookie1986 [14]

Answer:

420

Step-by-step explanation:

If there were 1200 people, and 65 percent were women, that means the rest of the crowd are men, which is 35 percent. By multiplying 35 percent by the overall population, 1200, (1200*35/100), you'll get 420 men.

4 0
3 years ago
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PLEAS HELP I REALLY NEED HELP
blsea [12.9K]

Answer:

the first one in the picture

Step-by-step explanation:

8x8x8x8=4096

9x9x9x9=6561

4096x6561=26873856

72x72x72x72=26873856

5 0
2 years ago
The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100
Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, \mu = 310/1000 or 0.31   and  Standard deviation, \sigma = 14.63/1000 = 0.01463 .

We know that Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

 P(X <=0.13) = P( \frac{X-\mu}{\sigma}  <= \frac{0.13-0.31}{0.01463} ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

4 0
3 years ago
The equation of a function<br>y = 2/3x+1/3 find the value of y<br>when x = -3<br>when x = 1 1/2​
kirill [66]

Answer:

y = \frac{-5}{3}\\\\y = \frac {4}{3}

Step-by-step explanation:

y = \frac{2}{3} x + \frac{1}{3}\\\\when \ x = -3 \\\\y = \frac{2}{3}(-3) + \frac{1}{3} = -2 + \frac{1}{3} = \frac{-6 + 1}{3}= \frac{-5}{3} \\\\When \ x = 1 \frac{1}{2} = \frac{3}{2}\\\\y = \frac{2}{3} \times \frac{3}{2} + \frac{1}{3} = 1+ \frac{1}{3} = \frac{3 + 1}{3}= \frac{4}{3} \\\\

5 0
3 years ago
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