Using derivatives, it is found that the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
The acceleration is the <u>derivative of the velocity</u>, given by change in velocity divided by change in time, that is:
In this problem:
- The change in time for objects C and T is the same.
- The <u>change in velocity for object C is greater</u>, thus, it has a greater acceleration, and the correct option is:
A. Object C has an acceleration that is greater than the acceleration for D.
A similar problem is given at brainly.com/question/14516604
Answer: 6.71
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Work Shown:
The longest horizontal portion of length 6 breaks up into two equal pieces of length 3 each. Focus on the smaller right triangle on the right hand side. This right triangle has legs of 3 and 6. The hypotenuse is x.
Use the pythagorean theorem with a = 3, b = 6, c = x to find the value of x
a^2 + b^2 = c^2
3^2 + 6^2 = x^2
9 + 36 = x^2
45 = x^2
x^2 = 45
x = sqrt(45)
x = 6.7082039
x = 6.71
Ooh so the directions tell us what we need to find the entire line, which is made up of FH. so just add GH (15) and FG (6) together to find FH. so that is 21. FH=21.
Y ≥ 2x-5
y-intercept is -5, from there go 2 up 1 over ( slope is rise over run)
greater than or equal so the line is connected
now find the shaded area by plugging in (0,0)
0 ≥2(0)-5
0 ≥-5 is correct so shade the area that to the left of the line, (the whole area that including (0,0))
y<-3x
y intercept is 0 so start from there and go down 3 right 1 (or go up 3 left 1)
broken like cause no or equal sign
the (0,0) is on the line so use (1,1) to find the answer
1<-3(1) is incorrect so shade the area that dies not include (1,1) or the entire area to the left of that line
you can see the section where both shaded area cross, thats the answer so erase every area you shaded that isn’t the answer so
THE ANSWER IS C
B) the additive inverse of -3 is +3, so 17-(-3) = 20 is your answer.
Remember, two negatives = one positive, and so:
- (-3) = 3
17 + 3 = 20
Therefore, B is your answer
hope this helps
