Answer:
Approximately
n = 21 years
Step-by-step explanation:
Original height of the tree = 4 1/2 feet
Final height of the tree = 40 feet
Common difference = 1 3/4 feet per year
The data shows the question is an arithmetic progression
Tn = a + (n-1) d
Tn = 40
a = 4 1/2
d = 1 3/4
n = ?
Tn = a + (n-1) d
40 = 4 1/2 + ( n - 1) 1 3/4
40 = 9/2 + (n - 1) 7/4
40 = 9/2 + 7/4n - 7/4
40 = 18-7/4 + 7/4n
40 = 11/4 + 7/4n
40 - 11/4 = 7/4n
160-11/4 = 7/4n
149/4 = 7/4n
Divide both sides by 7/4
n = 149/4 ÷ 7/4
= 149/4× 4/7
= 149/7
n = 21.29 years
Approximately
n = 21 years
Answer:
ii.
Step-by-step explanation:
Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The student is 6 feet tall. What is the height of the tree? Show all work
<em><u>Answer:</u></em>
Option D
The height of tree is 20 feet tall
<em><u>Solution:</u></em>
From given question,
Shadow of tree = 30 feet
Height of tree = ?
Height of student = 6 feet
Shadow of student = 9 feet
We have to find the height of tree
We can solve the sum by proportion

This forms a proportion and we can solve the sum by cross multiplying

Thus height of tree is 20 feet tall
Answer:
8
Step-by-step explanation:
just flip the number
hope dis helps ^-^