Please answer Parts A, B, and C. I Will Mark Brainliest

A polynomial function has a root of -3 with multiplicity 2, a root of 0 with multiplicity 1, a root og 1 woth multiplicity 1 and

damaskus [11]

25 is the answer hurry hurry

5 0

3 years ago

What is the solution set of y = x2 + 2x + 7 and y = x + 7? A. {(0, 7), (-1, 6)} B. {(0, 7), (-7, 0)} C. {(0, 7), (1, 8)} D. {(-2

Elena-2011 [213]

Answer:

A.

Step-by-step explanation:

If

$y=x^2+2x+7$ AND

y = x + 7, then by the transitive property of equality:

$x^2+2x+7=x+7$

We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:

$x^2+x=0$

We can factor out the common x to get:

x(x + 1) = 0

which tells us by the Zero Product Property that either

x = 0 and/or x + 1 = 0 and x = -1

We are expecting 2 solutions for x since this is a second degree polynomial. We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y

y = 0 + 7 so

y = 7 and the coordinate is (0, 7)

y = -1 + 7 so

y = 6 and the coordinate is (-1, 6)

8 0

3 years ago

Which expression has a positive value?

Black_prince [1.1K]

Answer:

3 (negative 64 divided by 8) + 25 = 1

Step-by-step explanation:

Negative 4 + (negative 5) (negative 6) divided by (negative 3) = -4 + (-5)(-6)/(-3) = -4 + 30/-3 = -4 - 10 = -14

8 Left-bracket 10 divided by (2) (negative 2) Right-bracket = 8(10/((2)(-2)) = -20

3 (negative 64 divided by 8) + 25 = 3(-64/8) + 25 = 3(-8) + 25 = -24 + 25 = 1

Negative 2 (negative 5) (negative 3) divided by 10 = (-2)(-5)(-3)/10 = -3

The only positive value here is 1, which is a result of 3 (negative 64 divided by 8) + 25

6 0

3 years ago

Read 2 more answers

Are the irrational numbers closed under addition?

Arte-miy333 [17]

Answer:

Irrational numbers are not closed under addition.

Step-by-step explanation:

Irrational numbers are the numbers that cannot be expressed in the form of a fraction $\frac{x}{y}$ . In other words we can say that irrational number,s decimal expantion does not cease to end.

The closure property of addition in irrational numbers say that sum of two irrational number is always a rational number, But this is not true. It is not necessary that the sum is always irrational some time it may be rational.

This can be understood with the help of an example:

let (2+√2) and (-√2) be two irrational number. Their sum is (2+√2)+(-√2) = 2, which is clearly a rational number.

Hence, irrational numbers are not closed under addition.

4 0

3 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago