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3 years ago

The model of the shark below uses a scale of 1.5 in = 3 ft

Mathematics

1 answer:

Lady_Fox [76]3 years ago

5 0

Answer:

Step-by-step explanation:

1.5 inch = 3 feet

1 in = 2 ft

2(5)

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What is the square root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B163%7D%20" id="TexFormula1" title=" \sqrt{163} " a

crimeas [40]

Hi,

$\sqrt{163} = 12.76$

There are no other simple steps to reduce the square root of one hundred and sixty-three.

The actual square root value is ≈12.767145334803704

But we have taken only significant figures and it is as 12.76.

Hope it helps! :)

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3 years ago

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a group of astronauts launched a model rocket from a platform. Its flight path is modeled by h= -4t^2+24t+13 where h is the heig

Eddi Din [679]

Answer:

6.5 seconds

Step-by-step explanation:

Keep in mind that when $h=0$ , this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:

$h=-4t^2+24t+13\\\\0=-4t^2+24t+13\\\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\t=\frac{-24\pm\sqrt{24^2-4(-4)(13)}}{2(-4)}\\ \\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{576+208}}{-8}\\\\t=\frac{-24\pm\sqrt{784}}{-8}\\\\t=\frac{-24\pm28}{-8}\\\\t=\frac{-24-28}{-8}\\ \\t=\frac{-52}{-8}\\ \\t=\frac{52}{8}\\\\t=6.5$

So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds

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3 years ago

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