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3 years ago

Brainliest, pls help

Mathematics

2 answers:

Zina [86]3 years ago

5 0

That will be the second one, square root of 34

horrorfan [7]3 years ago

4 0

B) 34 hope this is correct

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Please Help!!! Evaluate the following <br><br> 2/((3-(3-1))*3-1)

antiseptic1488 [7]

2/ 3 - (3 - 1) * 3 - 1 = -4
Simplify
= 2/-4
which is
= -2/4
Then simplify again
= -1/2

6 0

3 years ago

what is the completely factored form of t^4 − 16? (t^2 4)(t^2 − 4) (t^2 4)(t 2)(t − 2) (t^2 4)(t − 2)(t − 2) (t 2)(t 2)(t 2)(t −

Eva8 [605]

$Use:a^2-b^2=(a-b)(a+b)\\\\t^4-16=(t^2)^2-4^2=(t^2-4)(t^2+4)=(t^2-2^2)(t^2+4)=(t-2)(t+2)(t^2+4)$

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3 years ago

During which time period does Landon's elevation change the fastest? Explain how you know?

bogdanovich [222]

<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points $(4,3) \ and \ (8,6)$ why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min$

<em>So London's elevation changes 0.75 inches per minute</em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, $(16,5) \ and \ (18,3)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min$

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

7 0

3 years ago

Olution set for 8( 3x - 2)2(7x + 12)?

In-s [12.5K]

Answer: x ≤ 4
___________

6 0

3 years ago

Please put details! I need it!

Kay [80]

Answer:

a. the points will be in quadrants q and s

b. the difference between the coordinates of the starting point and the checkpoint is that the starting point is negative on the 5 axis while the checkpoint is positive. the number on the y axis for the staring point and the checkpoint is the same.

3 0

3 years ago