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grigory [225]
3 years ago
10

I gotta have this until 3:30pm please help-

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

They are, because similarity means that the ratio of the sides are equal and they are proportionate.

Step-by-step explanation:

If you look at the graph, you can count 2 units from the smaller diamond/rhombus to the other diamond/rhombus. If you count the amount of units on each side, you will find that they are not equal, however they should be proportional if you calculate the angles of 90°.

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Write an equation in slope intercept form for the line thepasses through (-1,-6) and is parallel to x+3y=6
enot [183]

Answer:

The slope-intercept form equation of the line that passes through (1, 3) and (3, 7) is y = 2x +1.

Step-by-step explanation:

7 0
2 years ago
Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3
k0ka [10]

Answer:

x = \frac{3}{2}

Step-by-step explanation:

Given

f(x) = \frac{x-4}{2x-3}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

Thus x = \frac{3}{2} is the vertical asymptote

5 0
3 years ago
Simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BX-10%7D" id="TexFormula1" title="\frac{1}{X-10}" alt="\frac{1}{X-10}
mr Goodwill [35]

In the second fraction, factorize the denominator:

x^2-9x-10=(x-10)(x+1)

Then we have, as long as x\neq10,

\dfrac1{x-10}\div\dfrac{9x}{x^2-9x-10}=\dfrac{\frac1{x-10}}{\frac{9x}{(x-10)(x+1)}}=\dfrac1{\frac{9x}{x+1}}=\dfrac{x+1}{9x}

which you could also write as

\dfrac{x+1}{9x}=\dfrac x{9x}+\dfrac1{9x}=\dfrac19+\dfrac1{9x}

4 0
2 years ago
Will give brainlyest if u help
goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>

  • <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
  • <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

   in some positions

∴ The graph does not represent a function because it fails the vertical

   line test

7 0
3 years ago
Round to the nearest tens 312.432
ValentinkaMS [17]
310, since 4 is not up to 5, then 2 round off to 0
8 0
3 years ago
Read 2 more answers
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