First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
Not 100 hundred percent sure but I believe the answer is c
First, convert both fractions into improper fractions:
-2 and 1/4= -9/4
-4 and 1/2= -9/2
Now we can find the product!
-9/4 x -9/2= 81/8
(Remember that when you multiply two negatives, the product turns positive)
And because 81/8 cannot be reduced, to find your final answer, just covert 81/8 into a mixed fraction!
81/8= 10 and 1/8
Hope this helps!
Answer:
see explanation
Step-by-step explanation:
Given
3
- 2x² + 15x² - 10
Factor the first/second and third/fourth terms )
= x²(3x² - 2) + 5(3x² - 2) ← factor out (3x² - 2) from each term
= (3x² - 2)(x² + 5)
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
