Answer:
x-coordinates of relative extrema = 
x-coordinates of the inflexion points are 0, 1
Step-by-step explanation:
Differentiate with respect to x
Differentiate f'(x) with respect to x
At x = ,
We know that if 
then x = a is a point of minima.
So, 
is a point of minima.
For inflexion points:
Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.
So, x-coordinates of the inflexion points are 0, 1
Answer:
3/7
Step-by-step explanation:
Please use " ^ " to denote exponentiation:
<span>f(x) = –(x + 8)^2 – 1
Find the first derivative: f '(x) = -2(x+8)(1)
Set this = to 0: -2(x+8) = 0
solve for x: x = -8
Divide the number line into subintervals based upon x=-8:
(-inf, -8) and (-8, inf)
Choose a test value for x from each interval, e. g., -10 from the first interval and 20 from the second.
Subst. this test value into the derivative, shown above.
If the result is + the function is incr on that interval; if - the fn. is decr.
Questions welcome!</span>
Answer: -6 That’s your answer.
Answer:
1) find d or distance between numbers
2) equation: an=a1+(n-1)d
3) an is nth term
a1 is first number in sequence
